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Strategy 07 of 12

Pigeonhole Principle

More pigeons than holes → some hole has two pigeons

ExistenceCountingCombinatorics
If $n+1$ objects are placed in $n$ categories, at least one category contains $\geq 2$ objects. Simple to state, but its applications are astonishing. Generalized: if $kn+1$ objects go in $n$ categories, some has $\geq k+1$.

When to use it

  • When the statement says 'at least' or 'there exist'
  • When you have more objects than categories
  • When searching for a guaranteed existence
  • In counting and combinatorics

How to think (step by step)

  1. 1Identify the 'pigeons': What are the objects?
  2. 2Identify the 'holes': What are the categories?
  3. 3Count: How many of each?
  4. 4Apply: If objects > categories, some category has 2+
  5. 5Conclude: This gives the required existence

Practice Problems

Three problems at increasing difficulty — try each before revealing the hint or solution.

📘Basic
In a room with \(13\) people, prove that at least \(2\) were born in the same month.
📙Intermediate
Choose \(5\) points inside an equilateral triangle with side length \(1\). Prove at least two are within distance \(\frac{1}{2}\) of each other.
📕Advanced
Prove: among any \(n+1\) integers chosen from \(\{1, 2, \ldots, 2n\}\), some two have the property that one divides the other.