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Strategy 07 of 12Pigeonhole Principle
More pigeons than holes → some hole has two pigeons
ExistenceCountingCombinatorics
If $n+1$ objects are placed in $n$ categories, at least one category contains $\geq 2$ objects. Simple to state, but its applications are astonishing. Generalized: if $kn+1$ objects go in $n$ categories, some has $\geq k+1$.
When to use it
- →When the statement says 'at least' or 'there exist'
- →When you have more objects than categories
- →When searching for a guaranteed existence
- →In counting and combinatorics
How to think (step by step)
- 1Identify the 'pigeons': What are the objects?
- 2Identify the 'holes': What are the categories?
- 3Count: How many of each?
- 4Apply: If objects > categories, some category has 2+
- 5Conclude: This gives the required existence
Practice Problems
Three problems at increasing difficulty — try each before revealing the hint or solution.
📘Basic
In a room with \(13\) people, prove that at least \(2\) were born in the same month.
📙Intermediate
Choose \(5\) points inside an equilateral triangle with side length \(1\). Prove at least two are within distance \(\frac{1}{2}\) of each other.
📕Advanced
Prove: among any \(n+1\) integers chosen from \(\{1, 2, \ldots, 2n\}\), some two have the property that one divides the other.