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χ!-χ^3+χ(χ!+1)=0 =>χ!-χ^3+χ*χ!+χ=0 =>χ!+χ*χ!=χ^3-χ =>χ(χ!+1)=χ(χ^2-1) => χ=0, χ=2
1 σχόλιο:
χ!-χ^3+χ(χ!+1)=0 =>
ΑπάντησηΔιαγραφήχ!-χ^3+χ*χ!+χ=0 =>
χ!+χ*χ!=χ^3-χ =>χ(χ!+1)=χ(χ^2-1) => χ=0, χ=2