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a1 = 2^4*3^0a2 = 2^3*3^1a3 = 2^2*3^2a4 = 2^1*3^3Συνεπώς a5 = 2^0*3^4 = 81ΔΔΛ Β'
a1 = 2^4*3^0
ΑπάντησηΔιαγραφήa2 = 2^3*3^1
a3 = 2^2*3^2
a4 = 2^1*3^3
Συνεπώς a5 = 2^0*3^4 = 81
ΔΔΛ Β'